Squares Quilting Blocks

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Can someone please give me another way to do this problem thanks?

Amelia made a quilt from his bed. His bed is 60 inches wide and 78 cm long. She wants the blanket that hangs over each side and end attleast 12 inches. The finished quilt blocks will be 6 inches square inch strip them and around with1.5 bettween the edges. What is the maximum number of seats, will? PLEASE HELP this is the method using 60 12 12 = 84 inches wide, 78 +12 = 90 inches Each block is 6 inches 1.5 7.5 84/7.5 = 11.2 90/7.5 = 12 to 11 * 12 = 132 The correct answer because he is my teacher and gave it to me I just need another way to figure this out. Please help you and thank you very much PS. If you leave two methods to the problem, you can be sure of 10 points.

To review your current method more as an equation: width of the quilt is> = 60 "+ 2 * 12"> 60in 24in + W => = 84 Let W = S number of places. Width of each square Quilt in June, More Than 1.5 "on the left side of each square. Then, to finish on the side of the quilt, you will need additional 1.5" on the right of the last four. How many squares across the width of the quilt? W = 6S + 1.5s + 1.5 + 1.5 W = 7.5S Now we can define the equality of these equations to find the number of places S everywhere. Remember that you only have a positive impact, the total number of seats (a physical element indivisible), we will have All Year. Remember that we can add or subtract / multiply / divide by the same amount for both parties with the same equation, while maintaining equality. (Multiplication / division by a negative one inequality is a special case, but we found only.) 7.5S + 1.5> = 84 7.5S 1.5 -1.5> = 84 to 1.5 7.5S> = 7.5S 82.5> = 82.5/7.5 S> = 11 , then we Must Have at least 11 seats in any width the quilt. Duration of the quilt is> = 78 "L + 12 inches> 12 inches 78in + => = 90 length of each quilt square is 6 more than 1.5 "on top of each square. Then, to finish the bottom of the quilt, you will need additional 1.5 "in the bottom of the last box. How squares throughout the quilt? L = 6S + 1.5s + 1.5 + 1.5 L = 7.5S Now we can put these equations achieve equal number of seats S along the length. Remember that we can have a positive impact, the total number of seats (an indivisible physical item) so we have to rounding. 7.5S + 1.5> = 90 + 7.5S from 1.5 to 1.5> = 90 to 1.5 7.5S> = 88.5 7.5S/7.5> = 88.5/7.5 S> = 11.8 (round ) S> = 12 therefore the quilt must be at least 11 seats and 12 seats in the lower, or 11 * 12 = 132 boxes is the minimum number of seats you need. Number Maximum places that Amelia needs to be done? therefore, the more you can do, because there is no limit on the final size of the quilt (only a limit to how small that is). However, a second method to calculate what is similar to the previous W> L = ...> 84 = 90 L *> W = 84 * 90 region of size> = 7560 a 6 "square with 1.5" top and left edge: 7.5 "* 7.5" = H1 = 56.25 There is also a 1.5 "x 1.5" square the border is not represented: 1.5 ^ 2 = 2.25 I'm going to ignore the rest of the background and right side of the border ... How many squares are needed to reach the size Minimum final quilt? 56.25 + 2.25> = 7560 + 56.25 2.25 2.25> 56.25 = 7560> = 7557.25 56.25S/56.25? 7557.25/56.25 => S = 134.36 (However, the equation true for the area is L = 1.5 7.5SW = 7.5S + 1.5 L * W = (1.5 7.5S) ^ 2 = area of 56.25 (S ^ 2) + 22 5 56.25 +2.25 (S ^ 2) + 22.5 + 2 25> = 7560 56.25 (S ^ 2) + + 22.05 2.25-7560> = 7.560 to 7.560 56.25 (S ^ 2) + 22.5-7557.75 = 0 using the quadratic equation to solve: (I took a shortcut and connected: http://www.mathsisfun.com/quadratic-equation-solver.html) S = 11.39 ... ... -11.79 District, and we need positive numbers: 12 * 12 = 144 boxes)